Matematika Sekolah Menengah Atas Quiz Veii ฅ^•ﻌ•^ฅ[tex]\tiny\tt {3!}^{2!} × {6}^{\sqrt{12 × 3}} ÷ {6}^{\frac{(10 × 2!)}{3! - 1!}}[/tex]​

mozelleswaniawskiulv – May 11, 2023

Quiz Veii ฅ^•ﻌ•^ฅ

[tex]\tiny\tt {3!}^{2!} × {6}^{\sqrt{12 × 3}} ÷ {6}^{\frac{(10 × 2!)}{3! - 1!}}[/tex]​

= 3!^2! × 6^(√12 × 3) ÷ 6^((10 × 2!)/(3! - 1!))

= 6² × 6^(√36) ÷ 6^((10 × 2)/(6 - 1))

= 6² × 6⁶ ÷ 6^(20/5)

= 6² × 6⁶ ÷ 6⁴

= 6^(2 + 6 - 4)

= 6⁴

Jawaban:

= 3!^2! × 6^(√12×3)) ÷ 6^((10×2!)/(3! - 1! ))

= 6^2 × 6^(36)) ÷ 6((10 × 2 ))/( 6 - 1! )

= 6^2 × 6^6 ÷ ( 20 / 6 - 1 )

= 6^2 × 6^6 ÷ ( 20 / 5 )

= 6^2 × 6^6 ÷ 6^4

= 6^( 2 + 6 - 4 )

= 6^( 8 - 4 )

= 6⁴

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